SOLUTION: What is the length of a rectangular parking lot which covers 28,000 square feet and is twice as long as it is wide?
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Question 739588: What is the length of a rectangular parking lot which covers 28,000 square feet and is twice as long as it is wide?
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
What is the length of a rectangular parking lot which covers 28,000 square feet and is twice as long as it is wide?
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Area = L*W = 28000
L = 2W
2W*W = 28000
W^2 = 14000
W = sqrt(14000)
L = 2sqrt(14000)
L =~ 236.64 feet
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
given:
-length
-width
if , then
if is twice as long as it is , then
..substitute in and solve for
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