SOLUTION: The height h above ground in feet of a ball dropped from the top of a 30 foot tall building after t seconds is given by the polynomial: h(t)= -16t^2+30. what is the height of the b

Algebra.Com
Question 739286: The height h above ground in feet of a ball dropped from the top of a 30 foot tall building after t seconds is given by the polynomial: h(t)= -16t^2+30. what is the height of the ball after 1/2 second?
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The height h above ground in feet of a ball dropped from the top of a 30 foot tall building after t seconds is given by the polynomial: h(t)= -16t^2+30. what is the height of the ball after 1/2 second?
------------
h(t)= -16t^2+30
--
Sub 1/2 for t to find h(1/2)

RELATED QUESTIONS

Need help finding the ho on this quadratic word problem the answer I tried to figure out... (answered by lwsshak3)
I need help with this problem, i dont know how to set it up! thanks! Suppose an object... (answered by josmiceli)
A ball is dropped vertically from the top of a building 450 meters above the ground. Its... (answered by ikleyn)
A ball is thrown straight up with an initial velocity of 80 feet per second from the top... (answered by josmiceli)
A ball is thrown vertically upwards from the top of a school building. It’s height, h... (answered by ikleyn)
Good morning, Any help on this one would be greatly appreciated. If a ball is... (answered by KMST)
A ball is dropped from a height of 784 ft. It's height h, in feet, after t seconds is... (answered by Alan3354)
A student dropped a ball from the top of a 64 foot building. The height of the ball... (answered by vleith)
A student dropped a ball from the top of a 81-foot building. The height of the ball after (answered by solver91311)