SOLUTION: Three sides of a right triangle are labeled as x-2, x+5 and x+6. I need to find X. I used the Pythagorean theorem and after all my calculations I came to x=6. However, when I pu

Question 722403: Three sides of a right triangle are labeled as x-2, x+5 and x+6. I need to find X. I used the Pythagorean theorem and after all my calculations I came to x=6. However, when I put it back into the theorem it does not add up. I am concerned I am doing something wrong in the algebra part of this equation. Can you help?
Here is my formula:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
I continue

(x-7)(x+1)=0
x= 7 Taking the positive value
Check
5^2+12^2
25+144=169

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