SOLUTION:
when 2 inches are added to each side of a square its area increase by 44 square inches. what was the perimeter of the initial square?
Algebra.Com
Question 711655:
when 2 inches are added to each side of a square its area increase by 44 square inches. what was the perimeter of the initial square?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
(X+2)^2=X^2+44
X^2+4X+4=X^2+44
X^2-X^2+4X=44-4
4X=40
X=40/4
X=10 INCHES FOR THE ORIGINAL SIDE OF THE SQUARE.
PROOF:
(10+2)^2=10^2+44
12^2=144
144=144
RELATED QUESTIONS
when 3 inches are added to each side of a square, its area increases by 57 square inches. (answered by ewatrrr)
the sides of a square are 10 inches long. if you increase each side by 50% by how many... (answered by ewatrrr)
When the sides of a square are each increased by 2feet its area increased by 44 feet.... (answered by scott8148)
A rectangular cutting board has an area of 112 square inches. Its perimeter is 44 inches. (answered by rothauserc)
the sides of square are 10 inches long. if you increase each side by 50% how many square (answered by ewatrrr,lwsshak3)
Each side of a square is increased 5 inches. When this happens, the area is multiplied by (answered by richwmiller)
Each side of a square is increased 6 inches. When this happens, the area is multiplied by (answered by macston)
Each side of a square is increased 4 inches. When this happens, the area is multiplied by (answered by ikleyn)
Each side of a square is increased 8 inches. When this happens, the area is multiplied by (answered by ikleyn)