SOLUTION: please help me solve this:
if the perimeter of square A is half the perimeter of aquare B, then the area of aquare B is how many times the area of aquare A?
thank you for your ti
Algebra.Com
Question 710129: please help me solve this:
if the perimeter of square A is half the perimeter of aquare B, then the area of aquare B is how many times the area of aquare A?
thank you for your time!
Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I'll say that the perimeter of the smaller square is
and the perimeter of the larger square is
That means a side of the smaller square is
and a side of the larger square is
Area of larger square =
Area of smaller square =
( area B ) / ( area A ) =
Area B is 4 times area A
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The perimeter of a square with side measure 
is 
. The area of such a square is 
.
A square with one-half the perimeter would have a perimeter of 
, hence the measure of one side would be 
. And the area of this smaller square is ^2)
.
^2)
Solve for 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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