SOLUTION: A 3 gallon mixture contain 1 part x and 2 parts y. In order to change it to a mixture containing 25%x, how much y should be added.

Question 696905: A 3 gallon mixture contain 1 part x and 2 parts y. In order to change it to a mixture containing 25%x, how much y should be added.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let A=amount of y that should be added:
The 3 gallon mixture initially contains 1/3 x and 2/3 y
Now we know that the amount of pure x that exists before the y is added ((1/3)*3) has to equal the amount of pure x that exists after the y is added (3+A)(1/4)
Sooooo
(1/3)*3=(1/4)*(3+A)
1=3/4 + (1/4)*A
1-(3/4)=(1/4)A
1/4=(1/4)A
A=1---gal of y needs to be added
CK
(1/3)*3=(1/4)*4
1=1
Hope this helps----ptaylor
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