SOLUTION: If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle.

Question 688173: If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle.
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Let the width be "w".
Then the length is "w+2".
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Use Pythagoras
w^2 + (w+2)^2 = (sqrt(11))^2
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w^2 + w^2 + 4w + 4 = 11
2w^2 + 4w - 7 = 0
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w = [-4 +- sqrt(16 - 4*2*-7)]/4
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w = [-4+- sqrt(72)]/4
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w = [-4 +-6sqrt(2)]/4
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Positive solution:
w = [-4 + 6sqrt(2)]
width = 1.12 cm
length = 3.12 cm
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Cheers,
Stan H.
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