SOLUTION: The length of a rectangle is 18 cm more than the width. A second rectangle is 6cm shorter and 3 cm wider than the first and has a perimeter of 126 cm. Find the dimensions of each

Question 682894: The length of a rectangle is 18 cm more than the width. A second rectangle is 6cm shorter and 3 cm wider than the first and has a perimeter of 126 cm. Find the dimensions of each rectangle.
This is what I tried.
(w -3) +( w-3) +( w + 18+3) +( w + 18+3) = 126
but it did not work out correctly
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

let be the length and the width of the first rectangle, and be the length and the width of the second rectangle
given:
The length of a rectangle is more than the width .
........eq. 1
A second rectangle is } shorter:
and wider than the first:
and has a perimeter of .....eg. 2
..substitute and

.........go to eq. 1, and substitute .
.....solve for

now find

now we can find sides of second rectangle:

check if

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