Hi,

The width of a rectangular box is 3 times its height 

and its length is 2 more than its height.

its volume is 288 cubic

Translate into an equation: 

 lwh = 288 in^3

(x+2)(3x)x = 288

  3x^3 + 6x^2 = 288

  3x^3 + 6x^2 - 288 = 0

   x^3 + 2x^2 -96 = 0   x = 4, one solution

  using Synthetic Divsion

4	1	2	0	-96

 	 	4	24	96

 	1	6	24	0

results in:  x^2 + 6x + 24  with imaginary roots

height is 4in, length 6in and width is 12in 

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