Hi,



base of an isosceles triangle is 24cm(PC=12) and one of its sides(AC=20) is 20cm long. 

 h(AP) = sqrt(20^2 - 12^2) = 16

 Centroid Distance from base(OP) =  

distance between the centroid and the vertex opposite the base(A0):





Donations on my web site are appreciated.  Thanks.  ewatrrr

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