SOLUTION: I need help on this problem, "A triangle has a perimeter of 108 yards. The first side is twice the length of the second side. The third side is 8 yards longer than the second side.

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Question 654643: I need help on this problem, "A triangle has a perimeter of 108 yards. The first side is twice the length of the second side. The third side is 8 yards longer than the second side. How long is each side?"
Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!




Solve for , then calculate and

John

My calculator said it, I believe it, that settles it
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Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
I need help on this problem, "A triangle has a perimeter of 108 yards. The first side is twice the length of the second side. The third side is 8 yards longer than the second side. How long is each side?"
--------------------------------
2nd side: x
1st side: 2x
3rd side: 2x+8
----
x + 2x + 2x+8 = 108
5x = 100
x = 20 yds.
2x = 40 yds
2x+8 = 48 hds
======
Cheers,
Stan H.
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