SOLUTION: how do you solve a rectangle that has length=20 W=10?
Algebra.Com
Question 640717: how do you solve a rectangle that has length=20 W=10?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
If you want the perimeter, then
P = 2L + 2W
P = 2*20 + 2*10
P = 60 units
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If you want the area, then
A = LW
A = 20*10
A = 200 square units
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