SOLUTION: good day! please help me with this word problem. thank you! The height of a painting is 16 inches greater than the width and the area of the painting is 720 square inches. Can i

Algebra.Com
Question 640394: good day! please help me with this word problem. thank you!
The height of a painting is 16 inches greater than the width and the area of the painting is 720 square inches. Can it be hung in a 2 feet by 4 feet wall space?

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
To answer this question, you'll need to find the height and width of the painting. Let h = the height and w = the width:
The area of the rectangular painting is expressed by:
but h = w+16 and A = 720, so making the appropriate substitutions, you get:
which, after some rearranging looks like:
Do you see how we get this? Now you can factor this quadratic:
which means that:
or Discard the negative solution as the width must be a positive quantity.
So the width is 20 inches and the height is 36 (20+16) inches.
Convert to feet:
Width = 1ft 8in.
Height = 3 ft.
So you can see that the painting will fit in the allocated space.

RELATED QUESTIONS

Good day! Can you please help me solve this problem? If the slant height of the cone (answered by Alan3354)
Good day SirMaam, Please help me solve this word problem: Thank you vey much. The sum (answered by Timnewman)
Good day Sir/Madam, please help me with this word problem. Your help means a lot. The (answered by Edwin Parker)
Please help me figure this problem out. The height of a right triangle is 7 inches... (answered by jorel1380)
Please Help Me Solve This Word Problem: the length of a rectangle is 8 inches greater... (answered by Gogonati)
I am having a difficult time with a word problem, could you please help me how to solve... (answered by josmiceli)
Good day to you. My daughter is having a problem with algebra word problems, can you... (answered by ReadingBoosters,Alan3354)
The base of a triangle is 4 inches less than twice the height. The area is 35 inches^2.... (answered by ankor@dixie-net.com)
Good day! Can you help me with this problem? Determine the area of the segment of the... (answered by Edwin McCravy)