SOLUTION: The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle.
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Question 63667: The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle.
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=width
Then 2x+10=length
P=2L+2W or
32=2(2x+10)+2x and
32=4x+20+2x collect like terms
6x=12
x=2 in
ck
2(2in)+2(14in)=32in
4+28=32
32=32
Hope this helps. Happy holidays----ptaylor
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