SOLUTION: the length of a rectangle is 8ft longer than twice the width. if the perimeter is 94ft, find the length and width of the rectangle.

Question 630018: the length of a rectangle is 8ft longer than twice the width. if the perimeter is 94ft, find the length and width of the rectangle.
Answer by Charles3475(23) (Show Source): You can put this solution on YOUR website!
Perimeter of a rectangle is 2*L + 2*W where L is the length and W is the width.

L = 2 * W + 8 (Given)

P = 2 * L + 2 * W (Definition of Perimeter for a Rectangle)

P = 94 feet (Given)

P = 2 * (2 * W + 8) + 2 * W (Substitution for L)

P = 4 * W + 16 + 2 * W (Multiplication)

P = 6 * W + 16 (Add like terms)

94 = 6 * W + 16 (Substitution for P)

78 = 6 * W (Subtract 16 from both sides)

13 = W (divide by 6)

W = 13 (Answer)

L = 2 * W + 8 (Given)

L = 2 * 13 + 8 (Substitution for W)

L = 34 (Simplify)

L = 34 (Answer)
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