SOLUTION: a rectangular field the perimeter of 314 yds. the width is 25 yds shorter than the length what are the dimensions?
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Question 627768: a rectangular field the perimeter of 314 yds. the width is 25 yds shorter than the length what are the dimensions?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If a rectangle with perimeter 
has a length 
that is 
units longer (or shorter if 
) than 
times the width, 
,
Then knowing that the Perimeter is given by:
,
make the substitution:
\ +\ 2w)
Then solve for
w\ =\ \frac{P\ -\ 2b}{2})
For your problem: 
, 
, and 
. Do the arithmetic.
John
My calculator said it, I believe it, that settles it
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