SOLUTION: The length of a rectangle is twice its width. When the length is increased by five and the width is decreased by three, the new rectangle will have a perimeter of 52. Find the dime
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Question 627528: The length of a rectangle is twice its width. When the length is increased by five and the width is decreased by three, the new rectangle will have a perimeter of 52. Find the dimensions of the original rectangle.
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
Let x = width
so 2x = length
2x + 5 = new length
x - 3 = new width
Perimeter = 2(2x + 5) + 2(x - 3) = 52, divide both sides by 2.
(2x + 5) + (x - 3) = 26
3x + 2 = 26
3x = 24
x = is the width of the original rectangle
2x = is the length of the original rectangle
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