SOLUTION: What is the capacity of a silo that is 30ft in height, the face against the barn is 10ft wide, and the barn is 5 ft. from the center of the circle?

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The intersection of the barn and silo is a secant line
that cuts across the circular base and is 10' long.
Draw a perpendicular from center of silo to the center of the secant.
Problem says center to the secant is 5". It divides the secant into
2 5' sections, forming 2 45-45-90 triangles. The area of the
base of the silo is therefore,




capacity is height X area of base

ft3
unless I made a mistake