SOLUTION: How do you solve for the dimensions of a rectangle given it's area of 160 and it is incribed in a circle with a diameter of 20

Question 594954: How do you solve for the dimensions of a rectangle given it's area of 160 and it is incribed in a circle with a diameter of 20
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
so the diagonal is 20

L * W = 160 (area equation)

L^2 + W^2 = 20^2 (Pythagoras)

2LW = 320

L^2 + 2LW + W^2 = 20^2 + 320 ___ (L + W)^2 = 4320 ___ L + W = 12√30

L^2 - 2LW + W^2 = 20^2 - 320 ___ (L - W)^2 = 3680 ___ L - W = 4√230
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