SOLUTION: A rectangle is twice as long as it is wide. if its length is increased by 6in and its width is incresed by 2in, its area is increased by 32in squared. find the original dimensions.
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Question 58530: A rectangle is twice as long as it is wide. if its length is increased by 6in and its width is incresed by 2in, its area is increased by 32in squared. find the original dimensions.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
L=2W
(2W+6)(W+2)=2W*W+32
2W^2+10W+12=2W^2+32
2W^2-2W^2+10W=32-12
10W=20
W=2
L=2*2
L=4
PROOF
2*4=8 IN^2
(4+6)(2+2)=2*4+32
10*4=40
40=40
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