an airplane over the pacific sights an atoll at a 5ー angle of depression. If the plane is 450 meters above water, how many kilometers is it from a point 450 meters above the atoll. x P覧覧覧覧覧覧覧覧覧覧覧覧覧覧覧猷 . 5ー | . |450 m . | . A Let the plane be at point P, the atoll at point A, and let Q be the point 450 m above the atoll at A. We want to find the distance PQ, which we will call x. QA = 450, and it is the side opposite the 5ー angle in right triangle PQA. PO = x = the side adjacent the 5ー angle in right triangle PQA. So since we are given the opposite side, and we want to find the adjacent side, we use the only one of the basic three trigonometric functions that involves the opposite and the adjacent, which is the tangent. So opp tan 5ー = ----- adj 450 tan 5ー = ----- x Multiply both sides by x: x tan 5ー = 450 Divide both sides by tan 5ー: 450 x = -------- tan 5ー Use a calculator 450 x = -------------- .0874886635 x = 5142.523535 Since 450 is rounded probably to the nearest 10 feet, we probably should round the final answer likewise, to 5140 feet. Edwin