SOLUTION: The length of a triangle is 4 m more than twice the length of the base. The area of the triangle is 35 m^2. Find the height of the triangle.
This is what I've done:
A=1/2*b*h
Algebra.Com
Question 566959: The length of a triangle is 4 m more than twice the length of the base. The area of the triangle is 35 m^2. Find the height of the triangle.
This is what I've done:
A=1/2*b*h
35= (1/2)*(2b)*(2b+4)
Is that the right equation? How do I solve this?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Missed it by that much (holding his thumb and index finger just a little bit apart).
Your equation:
(\underline{2}b)(2b\ +\ 4)\ =\ 35)
with the problem spot underlined. If you are going to use 
to represent the measure of the base, then is what goes in the equation to represent the base. You put in 
.
(b)(2b\ +\ 4)\ =\ 35)
is what you want.
Multiply 
by 
. Distribute across the parentheses. Add -35 to both sides.
Factor
(b\ -\ 5)\ =\ 0)
So 
or 
. Well, -7 for the measure of the base of a triangle is absurd, so toss that result out. The base is 5 and the height must be 14. And 5 times 14 is 70. 70 divided by 2 is 35. Answer checks.
John
My calculator said it, I believe it, that settles it
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