SOLUTION: This is the problem:
Can you show that no polygon exists in which the ratio of the number of diagonals of the sum of the measures of its interior angles is 1:18?
Here is my f
Algebra.Com
Question 563239: This is the problem:
Can you show that no polygon exists in which the ratio of the number of diagonals of the sum of the measures of its interior angles is 1:18?
Here is my formula:
n(n-3)/180(n-2)=1/18
I don't know if the n(n-3) part is the formula for finding the number of diagonals. What is the the correct formula and what steps should I take in solving this problem?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
This is the problem:
Can you show that no polygon exists in which the ratio of the number of diagonals of the sum of the measures of its interior angles is 1:18?
Here is my formula:
n(n-3)/180(n-2)=1/18
I don't know if the n(n-3) part is the formula for finding the number of diagonals. What is the the correct formula and what steps should I take in solving this problem?
-----------------------------
If the number of sides is n, the number of diagonals
= nC2 -n = (n(n-1))/2 - n = [n(n-1)-2n]/2 = [n^2-3n]/2 = [n(n-3)]/2
================================
Cheers,
Stan H.
=================
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