SOLUTION: The perimeter of a rectangular corral that has width x feet and length x +40 feet is 2(x) +2(x+40). Simplify the expression for the perimeter. Find the perimeter if x=30 ft.
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Question 55021: The perimeter of a rectangular corral that has width x feet and length x +40 feet is 2(x) +2(x+40). Simplify the expression for the perimeter. Find the perimeter if x=30 ft.
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangular corral that has width x feet and length x +40 feet is 2(x) +2(x+40). Simplify the expression for the perimeter. Find the perimeter if x=30 ft.
The formula for the perimeter of a rectangle is , where P=perimeter, W=width, and L=length.
P=2(x)+2(x+40) Distribute the 2
P=2(x)+2(x)+2(40)
P=2x+2x+80 Combine like terms.
P=(2+2)x+80
P=4x+80
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Substitute 30 in for x and simplify.
P=4(30)+80
P=120+80
P=200 ft (Don't forget your units.)
Happy Calculating!!!!
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