SOLUTION: The problem is...The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the fie

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Question 53763: The problem is...The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field.
I thought you would go length times width, but for some reason the added numbers are confusing me. wouldnt 5x-2x=230?
Answer by aaaaaaaa(138) (Show Source):
You can put this solution on YOUR website!
Length times width is the area, we want the perimeter, which is the sum of all the lengths of the sides (width+width+length+length).
Let's call width x. If the length is 5 less than twice x, it'll be 2x-5. Now we equal the perimeter to 230 and solve:

If the width is 60 ft, the length will be 2*60 - 5 = 115 ft.