You can
put this solution on YOUR website!Let x = width
y = length
Two equations:
2(x) + 2(y) = 60 Perimeter
xy = 200 Area
In the first equation, life is a lot easier if you divide both sides by 2 and write:
x + y = 30
From this you can solve for y by subtracting x from each side:
x -x + y = 30 - x
y = 30 - x
Now substitute this y = 30 -x into the other equation:
xy = 200
x(30 - x) = 200
Distributive property:
This is quadratic because of the
term, so you must set it equal to zero. To avoid the negative
term, take it to the right side by adding
and
to each side.
You can factor this or use the quadratic formula. Can you think of two numbers whose product is 200 and whose sum is 30? (Try 20 and 10!)
or
Remember that y = 30 - x.
If x = 20, then y = 10.
If x = 10, then y = 20.
It is appropriate to think of the width as being 10 meters and the length 20 meters.
R^2 at SCC
