SOLUTION: I am building a fence around a rectangular area. The length is twice it's width. The area is 2,450 squared feet. How much fencing materials do I need?
Please show work
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Question 536490: I am building a fence around a rectangular area. The length is twice it's width. The area is 2,450 squared feet. How much fencing materials do I need?
Please show work
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I am building a fence around a rectangular area. The length is twice it's width. The area is 2,450 squared feet. How much fencing materials do I need?
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It's square feet, not squared feet.
and, it's = it is
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Area = 2450 = L*W
L = 2W
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2450 = 2W*W = 2W^2
W^2 = 1225
W = 35 ft, L = 70 ft
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Perimeter = 2L + 2W = 210 feet
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