SOLUTION: The length of a rectangle is 7 m less than twice the width. If the lenght is decreased bi 1mand the width by 4 m, the perimeter will be 66 m. Find the demensions of the original re

Question 53620: The length of a rectangle is 7 m less than twice the width. If the lenght is decreased bi 1mand the width by 4 m, the perimeter will be 66 m. Find the demensions of the original rectangle.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!

The length of a rectangle is 7 m less than twice the width. If the lenght is decreased bi 1mand the width by 4 m, the perimeter will be 66 m. Find the demensions of the original rectangle.
THERE IS AN APPARENT ERROR.IF WE REDUCE L AND W BY 1 AND 4 M.,WHATEVER MAY BE THE VALUE OF L AND W,THE PERIMETER GETS REDUCED BY 1+4+1+4=10 M.AND NOT 66 M..PLEASE CHECK UP AND COME BACK
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