SOLUTION: If the area of a trapezoid is 32 and base 1 is x + 6 and base 2 is x+2 and the height = x, how can i solve for x?

Question 526077: If the area of a trapezoid is 32 and base 1 is x + 6 and base 2 is x+2 and the height = x, how can i solve for x?
Answer by Maths68(1474) (Show Source): You can put this solution on YOUR website!
Base 1 = x+1
Base 2 = x+2
Height = x
Area = 32
Area of a trapezoid = height * (sum of two bases)/2
32=x*(x+1+x+2)/2
32=x(2x+3)/2
32*2=2x^2+3x
64=2x^2+3x
2x^2+3x-64=0
a=2, b=3, c=-64

or
or
or
or (inadmissible)

Base 1 = x+1 = 4.96+1 = 5.96
Base 2 = x+2 = 4.96+2 = 7.96
Height = x = 4.96
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