SOLUTION: Perimeter of a field is 94ft. The width is 7 more than twice the length. What is the length and width?
Could you show or tell me how you solved this?
Thanks
Algebra.Com
Question 521299: Perimeter of a field is 94ft. The width is 7 more than twice the length. What is the length and width?
Could you show or tell me how you solved this?
Thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Perimeter of a field is 94ft. The width is 7 more than twice the length. What is the length and width?
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Let the length be "x".
Then the width = "2x+7".
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Perimeter = 2(length + width)
94 = 2(x + 2x+7)
47 = x + 2x + 7
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40 = 3x
x = 40/3 = 13 1/3
length = x = 13 1/3 ft.
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width = 2x+7 = 26 2/3 + 7 = 33 2/3 ft
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Cheers,
Stan H.
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