SOLUTION: the length of a rectangle is 12cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectanlge and has a perimeter of 68cm. Wha
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Question 513800: the length of a rectangle is 12cm more than its width. A second rectangle is 3cm shorter in width and 5cm longer in length than the first rectanlge and has a perimeter of 68cm. What are the dimensions of the second rectanlge?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the measure of the width of the first rectangle. Then 
is the measure of the length of the first rectangle, 
is the measure of the width of the second rectangle, and 
is the measure of the length of the first rectangle.
The perimeter of a rectangle is given by two times the length plus two times the width, hence:
\ +\ 2(w\ -\ 3)\ =\ 68)
Solve for , then calculate 
and
John
My calculator said it, I believe it, that settles it
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