SOLUTION: i need to find the counterexample to this conjecture: All rectangles with a perimeter of 20ft have the same area. note: perimeter= 2(Length+Width)

SOLUTION: i need to find the counterexample to this conjecture: All rectangles with a perimeter of 20ft have the same area. note: perimeter= 2(Length+Width)

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Question 487566: i need to find the counterexample to this conjecture: All rectangles with a perimeter of 20ft have the same area. note: perimeter= 2(Length+Width)
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
There are lots of counterexamples, so you do not need to refer to it as "the counterexample."

For example, a 4 ft * 6 ft rectangle and a 3 ft * 7 ft rectangle both have perimeter 20 ft, but their areas are different (24 ft^2 vs. 21 ft^2).
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