# SOLUTION: The perimeter of a rectangle is 50 ft. Describe the possible length of a side if the area of the rectangle is not to exceed 114 square feet. L * W > 114 2(L * W) = 50 L +

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 Click here to see ALL problems on Geometry Word Problems Question 474310: The perimeter of a rectangle is 50 ft. Describe the possible length of a side if the area of the rectangle is not to exceed 114 square feet. L * W > 114 2(L * W) = 50 L + W = 25 -W -W L = 25 – W Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!The perimeter of a rectangle is 50 ft. Describe the possible length of a side if the area of the rectangle is not to exceed 114 square feet. L * W > 114 2(L * W) = 50 L + W = 25 -W -W L = 25 – W ----------------- It's L*W <= 114 for "not to exceed" Sub for L W*(25-W) <= 114 W^2 - 25W + 114 <=0 (W - 6)*(W - 19) <= 0 --> 6 or 19 W = 6, L = 19 or W = 19, L = 6 -------------- W <= 6 for area <= 114 If one side is <= 6, the area is <= 114.