SOLUTION: find 3 consecutive odd numbers where the product of the smaller two numbers is 46 less than the square of the largest number

Question 472955: find 3 consecutive odd numbers where the product of the smaller two numbers is 46 less than the square of the largest number
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find 3 consecutive odd numbers where the product of the smaller two numbers is 46 less than the square of the largest number
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1st: x-1
2nd: x
3rd: x+1
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Equation:
x(x-1) = (x+1)^2-46
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x^2-x = x^2+2x-45
-x = 2x-45
-3x = -45
x = 15
x-1 = 14
x+1 = 16
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Cheers,
stan H.
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