SOLUTION: "Two angles of a triangle have equal measures, but the third angle's measure is 36� less than the sum of the other two. Find the measure of each angle of the triangle." This is

Question 468109: "Two angles of a triangle have equal measures, but the third angle's measure is 36� less than the sum of the other two. Find the measure of each angle of the triangle."
This is the problem I was given but how do I write it out? Normally, I would try to solve the problem before coming here but obviously I don't know where to start.
Also, what formula am I following; perimeter or area?
NOTE: I think I may able be to figure the problem out once I have been able to write the problem out correctly.

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
Draw a triangle and label is ABC.
Let angle A = x
let angle B = x
let angle C = 2x - 36
2x - 36 means that angle C is 36 degrees less than the sum of angle A and B.
Since the sum of the interior angles of a triangle is 180 degrees, then 2x + 2x - 36 = 180.
combine like terms in that equation and you get 4x - 36 = 180
add 36 to both sides of that equation and you get 4x = 216
divide both sides of that equation by 4 and you get x = 54 degrees
angle A = 54 degrees
angle B = 54 degrees
angle C = 108 - 36 = 72 degrees
54 + 54 + 72 = 108 + 72 = 180 degrees so the angles are good because they add up to 180 degrees and the third angle is 36 degrees less than the sum of the other 2.

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