Question 457019: h= 16t+28f+6,where height,h,is in feet and the time,t,is in seconds.How long does it take for this ball to reach a height of 12 feet? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! I think your formula should be:
h= -16t^2+28t+6
Now, you set h to 12 and solve for t:
12= -16t^2+28t+6
0 = -16t^2+28t-6
0 = -8t^2+14t-3
0 = 8t^2-14t+3
factoring we have:
0 = (4t-1)(2t-3)
t = {1/4, 3/2}
it reaches a height of 12 feet at:
1/4 second (on the way up)
and again at
3/2 second (on the way down)
