SOLUTION: Geometry. The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the demensions of the rectangle.

Question 44153This question is from textbook Begining Algebra
: Geometry. The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the demensions of the rectangle. This question is from textbook Begining Algebra

Answer by adamchapman(301) (Show Source): You can put this solution on YOUR website!
L = length
W = width
P = perimeter = 34
The length of the rectangle is 2 inches more than twice its width:
L = 2W + 2..............(i)
The perimeter is the sum of all side lengths:
P = 2W +2L..............(ii)
Subtitute equation (i) into (ii) for L:
P = 2W +2(2W + 2)
P = 2W + 4W + 4
P = 6W + 4
P = 34
6W + 4 = 34
6W = 30
W = 5 in.
Subtitute W=5 into equation (i) for W:
L = 2(5) + 2
L = 12 in.
I hope this helps
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk

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