SOLUTION: If an object is thrown upward with an initial velocity of 48 ft/secs its height after t sec is given by h equals 48t - 16t^2. Find the number of seconds before the object hits the

SOLUTION: If an object is thrown upward with an initial velocity of 48 ft/secs its height after t sec is given by h equals 48t - 16t^2. Find the number of seconds before the object hits the

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Question 439660: If an object is thrown upward with an initial velocity of 48 ft/secs its height after t sec is given by h equals 48t - 16t^2. Find the number of seconds before the object hits the ground.
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!

<==> 16t(3-t) = 0
==> t = 0,3.
t = 0 corresponds to the moment it was thrown upward, while
t = 3 corresponds to the time(sec) after which the object hits the ground.
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