SOLUTION: 1. The perimeter of a rectangle with length twice its width is equal to twenty-four. Write an algebraic equation to represent this situation, then solve for the length and width
Hi
length twice its width
Let x and 2x represent the width and length respectively
2*2x + 2*x = 24
6x = 24
x = 4 units, the width. The length is 8 units
CHECKING our Answer***
2*4 + 2*8 = 8 + 16 = 24