SOLUTION: Hi There, I need help in math but i was just wondering if you could help me with this problem: Solve for X. Then Classify the triangle by its angle meausures. Angle#1:90;angle#2

Question 433577: Hi There,
I need help in math but i was just wondering if you could help me with this problem: Solve for X. Then Classify the triangle by its angle meausures.
Angle#1:90;angle#2:X;angle#3:(X+20)
Here's what I've tried:
First I put it in an equation:90+(X+20)+X
Next I thought i was supposed to distribute,so I did:90 times X=90x + 90 times 20=1800(90x+1800=180)
But 180 is smaller than 1800..and that's where I got Stuck.. Please Help me and Thanks for trying
-Heaven C.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve for X. Then Classify the triangle by its angle meausures.
Angle#1:90;angle#2:X;angle#3:(X+20)
Here's what I've tried:
First I put it in an equation:90+(X+20)+X
:
Right here you should write the equation as:
90 + x + (x+20) = 180; (the total of all triangles)
Subtract 90 from both sides; combine like terms and you have
2x + 20 = 90
Subtract 20 from both sides
2x = 70
x = 35 degrees is the 2nd angle
and
35 + 20 = 55 degrees is the 3rd angle
:
:
You can confirm this 90 + 35 + 55 = 180
:
Obviously it is a Right triangle because it has a 90 degree angle

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