SOLUTION: the perimeter of a rectangle is 140 yards. if the length is 20 yards less than twice the width , find the length and width.
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Question 417985: the perimeter of a rectangle is 140 yards. if the length is 20 yards less than twice the width , find the length and width.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"the perimeter of a rectangle is 140 yards. if the length is 20 yards less than twice the width , find the length and width."
x = width
2x - 20 = length {length is 20 less than twice width}
Perimeter of a rectangle = (2 x width) + (2 x length)
2x + 2(2x - 20) = 140 {perimeter is 2(width) + 2(length)}
2x + 4x - 40 = 140 {used distributive property}
6x - 40 = 140 {combined like terms}
6x = 180 {added 40 to both sides}
x = 30 {divided both sides by 6}
2x - 20 = 40 {substituted 30, in for x, into 2x - 20}
width = 30yds and length = 40yds
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