Hi

points (-2,1),(a,b) and (4,-1) are collinear

Using the point-slope formula, 

(-2,1 and 

(4,-1)   m =  2/ -6 = -1/3

(-2,1),

(a,b)    |Question states: (a-b) = 1, a = 1+b

(1-b) / (-2-(1+b))     |substituting for a

(1-b)/ (-3 - b) = -1/3 

  -1(-3-b) = 3(1-b)    |cross multiplying

    3 + b = 3 - 3b

        4b = 0

         b = 0  and a = 1    (a = 1+b)

CHECKING our Answer***

(-2,1),

(1,0)  m = 1/-3   

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