SOLUTION: Deret geometri 2+2^2+2^3+....+2^n=254, n=....?

Algebra.Com
Question 398083: Deret geometri 2+2^2+2^3+....+2^n=254, n=....?
Answer by Tatiana_Stebko(1539)   (Show Source): You can put this solution on YOUR website!
sum of the n numbers in a geometric progression

a=2, r=2
S=254





RELATED QUESTIONS

n^-2/n^3 (answered by funmath)
(n+3)(2n+3)=(n+2)^2+(n-2)^2 (answered by stanbon,MathLover1)
2+2=n... (answered by edjones)
n+3/n+2 =... (answered by tazoftroy)
n/2 = 3/16 n = ????? (answered by rfer)
(n+1)! /... (answered by swincher4391)
-4 n( n+ 2) =... (answered by stanbon)
-21=n/3+2 (answered by checkley77)
3^n-2=27 (answered by Fombitz)