# SOLUTION: 12.Mr. Coyne has some dimes and quarters. He has twice as many dimes as quarters. The total value of his coins is \$8.10. How many dimes does he have?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Geometry -> SOLUTION: 12.Mr. Coyne has some dimes and quarters. He has twice as many dimes as quarters. The total value of his coins is \$8.10. How many dimes does he have?       Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Geometry Solvers Lessons Answers archive Quiz In Depth

 Question 39034This question is from textbook : 12.Mr. Coyne has some dimes and quarters. He has twice as many dimes as quarters. The total value of his coins is \$8.10. How many dimes does he have? This question is from textbook Found 2 solutions by stanbon, checkley71:Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!Mr. Coyne has some dimes and quarters. He has twice as many dimes as quarters. The total value of his coins is \$8.10. How many dimes does he have? Let the number of quarter be "x". Value of these quarters is 25x cents The number of dimes is "2x" Value of these dimes is 10(2x)=20x cents EQUATION: value + value = 810 cents 25x+20x=810 45x=810 x=18 (number of quarters) 2x=36 (number of dimes) Cheers, Stan H. Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!810=2x*10+x*25 or 810=20x+25x or 810=45x or x=810/45 or x=18 quarters then he has 36 dimes proof 36*10+18*25=810 or 360+450=810 or 810=810