SOLUTION: help please and thank you
A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at v
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Question 380509: help please and thank you
A launched rocket has an altitude, in meters, given by the polynomial h+vt-4.9t^2, where h is the height, in meters, from which the launch occurs, at velocity v in meters per second, and t is the number of seconds for which the rocket is airborne. If a rocket is launched from the top of a tower 70 meters high with an initial upward speed of 80 meters per second, what will its height be after 2 seconds?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
All you have to do is plug in the numbers and do the arithmetic.
The actual function should be rendered thus:
\ =\ -4.9t^2\ +\ v_ot\ +\ h_o)
Where )
is the height as a function of time, 
, 
is the initial velocity, and 
is the initial height. For your situation you would write:
\ =\ -4.9t^2\ +\ 80t\ +\ 70)
And you want the value of the function at time 
, so:
\ =\ -4.9(2)^2\ +\ 80(2)\ +\ 70)
Then just do the arithmetic.
John
My calculator said it, I believe it, that settles it
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