SOLUTION: a pile contains 1200 coins. Each day penny nichols takes 20% of the coins from the pile. Approximately how many coins remain in the pile after 7 days? thank you sooo much!!

Question 37885This question is from textbook
: a pile contains 1200 coins. Each day penny nichols takes 20% of the coins from the pile. Approximately how many coins remain in the pile after 7 days?

thank you sooo much!! This question is from textbook

Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
If we have 1200 coins on day zero and we remove 20% on day one, then 80% remains...
D0 = 1200
D1 = 1200(.8)
D2 = 1200(.8)(.8)
D3 = 1200(.8)(.8)(.8)
.
.
.
D7 = 1200(.8)^7 = 251+ coins
This is not a great problem because of the fractions of coins, but that is about it...
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