SOLUTION: I am haveing problems solving this problem I have tried numerous times but i just do not understand it. A rectangle is 5 times as long as it is wide. If the area is 125 square

Question 374746: I am haveing problems solving this problem I have tried numerous times but i just do not understand it.
A rectangle is 5 times as long as it is wide. If the area is 125 square feet, find its perimiter.
Answer by andsrox(1) (Show Source): You can put this solution on YOUR website!
the area of a rectangle = L x W
L = 5W
area = w x 5w
area =
125 =
=
= 5w
= 5w
AMP Parsing Error of [[5*sqrt(5) / 5]: Invalid expression '[5*sqrt(5)/5': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . = 5L / 5
= w
L/5 = w
L =
perimeter = 2W + 2L
p = + 2*5*sqrt(5)}}}
p = + 10*sqrt(5)}}}
p =
This was my best guess. Sorry if its wrong.
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