SOLUTION: The Length of a rectangle is twice its width. A second rectangle which is 8cm larger and 3 cm narrower than the first rectangle, has a perimeter of 154 cm. Make a sketch (you don't

Question 359530: The Length of a rectangle is twice its width. A second rectangle which is 8cm larger and 3 cm narrower than the first rectangle, has a perimeter of 154 cm. Make a sketch (you don't have to ) of the rectangles expressing all dimensional terms of w. Then find the dimensions of each rectangle.
Dolciani P.123 # 8
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The Length of a rectangle is twice its width. A second rectangle which is 8cm larger and 3 cm narrower than the first rectangle, has a perimeter of 154 cm. Make a sketch (you don't have to ) of the rectangles expressing all dimensional terms of w. Then find the dimensions of each rectangle.
Dolciani P.123 # 8
let width of first rectangle be x
length =2x
second rectangle
x+8
2x-3
Perimeter = 154
Perimeter = 2(L+W)
2*(x+8+2x-3)=154
2(3x+5)=154
6x+10=154
6x=144
x=24 width of first rectangle.
length = 48
...
second rectangle
width = 32
length = 45
...
m.ananth@hotmail.ca

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