You can
put this solution on YOUR website!Draw a straight line to denote the wall. Draw three more straight lines to create a rectangle.
Let 2 lengths of pen coming off the wall both be x.
The third length of te pen is therefore 36-2x in length.
Area, A = x(36-2x)
Now there are 2 methods to find the maximum value.
1. Find the roots of this equation (where the curve crosses the x-axis). The maximum point on the curve will then lie equidistant from these two, since ALL parabolas are symmetric in shape.
2. Use differentiation to find the maximum value directly.
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1.

so x=0 or 36-2x = 0
x=0 or 2x=36
x=0 or x=18
You can see this if i plot the graph:
By knowing that a quadratic is symmetrical about the turning point, then roots are at x=0 and x=18, so the turning point, the maximum here, is at x=9.
So dimensions of the pen are 9x18. This makes the max area 162.
2.

differentiate to find the turning point directly:

4x = 36
--> x = 9
So, the maximum is at x=9. Area is as before
jon.