SOLUTION: The length of a rectangle is six feet more than the width, If the perimeter is 32 feet, what are the length and the width?
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Question 310653: The length of a rectangle is six feet more than the width, If the perimeter is 32 feet, what are the length and the width?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
P=2L+2W
L=W+6
32=2(W+6)+2W
32=2W+12+2W
32=4W+12
4W=32-12
4W=20
W=20/4
W=5 ANS. FOR THE WIDTH.
L=5+6=11 ANS FOR THE LENGTH.
PROOF:
32=2*11+2*5
32=22+10
32=32
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